Join Our Email Alerts-Subscribe
Important Note:Login & Check Your Email Inbox and Activate Confirmation Link



Enter Your Email :

Copyright Disclaimer:
Section 107 of the Copyright Act Fair Use Contents .
We are forwarding content link(s) from our website to content website & We are not serving any contents.
Main Source:Google.com.All the Content PDF link(s) is/are obtained from GoogleSearch
for the purpose of Education & Teaching Intention. Not for commercial purpose.
Technicalsymposium.com is not liable/responsible for any copyright issues.

Placement Materials & Answers-Free Download


Software Companies Placement Papers With Answers- Atos Origin-Free Download

1. Two successive discounts are 20% 40% then its equivalent discount

2. If radius of cylinder is increased by 30% and height is decreased by 40% then what will % effect on volume of cylinder.

3.The total expense of a boarding house are partly fixed and partly variable with the number of boarders. The charge is Rs.70 per head when there are 25 boarders and Rs.60 when there are 50 boarders. Find the charge per head when there are 100 boarders.

a) 65

b) 55

c) 50

d) 45

soln.

a = fixed cost and

k = variable cost and n = number of boarders

total cost when 25 boarders c = 25*70 = 1750 i.e. 1750 = a + 25k total cost when 50 boarders c = 50*60 = 3000 i.e. 3000 = a + 50k solving above 2 eqns, 3000-1750 = 25k i.e. 1250 = 25k i.e. k = 50 therefore, substituting this value of k in either of above 2 eqns we get a = 500 (a = 3000-50*50 = 500 or a = 1750 - 25*50 = 500) so total cost when 100 boarders = c = a + 100k = 500 + 100*50 = 5500 so cost per head = 5500/100 = 55

4.Amal bought 5 pens, 7 pencils and 4 erasers. Rajan bought 6 pens, 8 erasers and 14 pencils for an amount which was half more than what Amal had paid. What % of the total amount paid by Amal was paid for pens?

a) 37.5%

b) 62.5%

c) 50%

d) None of these

soln.

Let, 5 pens + 7 pencils + 4 erasers = x rupees

so 10 pens + 14 pencils + 8 erasers = 2*x rupees

also mentioned, 6 pens + 14 pencils + 8 erarsers = 1.5*x rupees

so (10-6) = 4 pens = (2-1.5)x rupees

so 4 pens = 0.5x rupees => 8 pens = x rupees

so 5 pens = 5x/8 rupees = 5/8 of total (note x rupees is total amt paid by

amal) i.e 5/8 = 500/8% = 62.5% is the answer

(5) 2 oranges, 3 bananas and 4 apples cost Rs.15. 3 oranges, 2 bananas, and 1 apple costs Rs 10. What is the cost of 3 oranges, 3 bananas and 3 apples?

a) 10 b) 20 c) 30.45 c) 15

soln. of 5.

2x+3y+4z=15

3x+2y+z=10

adding

5x+5y+5z=25

x+y+z=5 that is for 1 orange ,1 bannana and 1 apple requires 5Rs.

so for 3 orange ,3 bannana and 3 apple requires 15Rs.

i.e. 3x+3y+3z=15

(6) Age of Mohan's sister is thrice of Mohan's age then what will be sister's age if Mohan's age is 4 year at present. some questions are also from data interpretation. i can't remember other questions but these question certainly give you some ideas. about question level

(7) Amith and Binith invested Rs.30000 and Rs.40000 respectively in a business for one year If they earned Rs 7,700 at the end of the year then the find Bs proft?

Rs,3,800 b)Rs.3,300 c)Rs.4,000 d)Rs.4,400

(8)There are 6 boxes numbered 1, 2,...6. Each box is to be filled up either with a red or a green ball in such a way that at least 1 box contains a green ball and the boxes containing green balls are consecutively numbered. The total number of ways in which this can be done is

If only one of the boxes has a green ball, it can be any of the 6 boxes. So, this can be achieved in 6 ways.

If two of the boxes have green balls and then there are 5 arrangement possible. i.e., the two boxes can one of 1-2 or 2-3 or 3-4 or 4-5 or 5-6.

If 3 of the boxes have green balls, there will be 4 options in which the 3 boxes are in consecutive positions. i.e., 1-2-3 or 2-3-4 or 3-4-5 or 4-5-6

If 4 boxes have green balls, there will be 3 options. i.e., 1-2-3-4 or 2-3-4-5 or 3-4-5-6

If 5 boxes have green balls, then there will be 2 options. i.e., 1-2-3-4-5 or 2-3-4-5-6

If all 6 boxes have green balls, then there will be just 1 options.

Total number of options = 6 + 5 + 4 + 3 + 2 + 1 = 21.

(9) A runs 13/5 times as fast as B. If A gives a start of 240m, how far must the post be so that A and B might reach at the same time.

A runs 13/5 times fast as B which means A runs 13 metres for every 5 meters of B.

Therefore, A gains 8 metre in a 11m race or if A gives a start of 8m in a 13m race then the race might end in a dead heat.

Therefore, if A gives a start of 240m (8* 30) then the length of the race should be equal to 13*30 = 390m

Or the length of the race after A gives a start of 240 start so that A and B reach at the same time is given by (240*13) /8 = 390m.

Source: Contents are provided by Technicalsymposium Google Group Members.
Disclaimer: All the above contents are provided by technicalsymposium.com Google Group members.
Further, this content is not intended to be used for commercial purpose. Technicalsymposium.com is not liable/responsible for any copyright issues.

Placement Papers & Answers PDF-Download



Aptitude & Placement Papers & Answers PDF



Technicalsymposium.com-All Study Materials PDF-Free Download







Technicalsymposium.com-Free Live Support-Chat with Our Experts

Official Contact: +91-9245556793 (Whatsapp Message / SMS / Voice Call)


Our Expert team is ready to answer all your questions immediately-Feel free to speak in Tamil/English.

(Example:Events info/Lecture Notes/Off-Campus & All Jobs/Projects & All education information)

Working hrs (IST): (Morning: 10:00AM-3:00 PM) and (Evening:5:00 PM to 10:00 PM)

All Latest Question & Answer Page (FAQ)-Click here