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Placement Materials & Answers-Free Download


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Qn.1 A tank has 2 pipes A and B which can fill a tank in 4 hrs and 6 hrs respectively. Another pipe C can empty the tank in 4 hrs. A man wanted to set a timer which should open the pipe C after the tank is half filled, but by mistake sets it to open when the tank is one fourth empty. The man was supposed to reach the place at the same time as the tank fills. How late was the man to reach the spot? (Pipes & Cisterns)

24 minutes

36 minutes

48 minutes

54 minutes

Answer:

54 minutes

Explanation:

The man will be late by the difference in time it takes to fill one fourth the tank in the two scenarios. i.e., 1 / 4(1/4 + 1/6 – 1/4) – 1 / 4(1/4 + 1/6) = 12/3 - 15/3 = 9/10 hours = 54 minutes.

Qn.2 Ajay has a four digit sum of money. If he is able to divide it among his 22 friends and himself equally when he spends Rs.19, what is the maximum possible amount with Ajay initially?

9978

Answer:

9978

Explanation:

Explanation: x- 19 should be divisible by 23

9995

9972

9977

Qn.3 Consider the sum of first 70 natural numbers. If every digit '6' is replaced by '8' what would be the net increase and the new sum?

16 & 2501

Answer:

16 & 2501

Explanation:

To answer this question, you need to know the simple formula for sum of first 'n' natural numbers which is n (n+1)/2. Hence sum of numbers from 1 to 70 would be 70X71/2 = 2485. If every '6' digit is replaced by '8' there would be totally 8 replacements at (6,16,26,36,46,56,60,66). Every replacement will add an additional '2' to the net sum. Hence the new sum will be 2485 + 8 X 2 = 2501 and the increase will be 16.

16 & 3501

14 & 2501

14 &3501

Qn.4 3 blocks are chosen randomly on a chessboard. What is the probability that they are in the same diagonal?

3/452

4/564

1/372

Answer: 1/372

Explanation:

There are total of 64 blocks on a chessboard. So 3 blocks can be chosen out of 64 in 64C3 ways. So the sample space is = 41664 There are 2 diagonal on chessboard each one having 8 blocks. Consider one of them. 3 blocks out of 8 blocks in diagonal can be chosen in 8C3 ways. But there are 2 such diagonals, hence favourables = 2 * 8C3 = 2 * 56 = 112 The require probability is = 112 / 41664 = 1 / 372

3/546

Qn.5 What is the area of the triangle ABC with A(e,p) B(2e,3p) and C(3e,5p)? where p = PI (3.141592654)

6.5467

8.3468

0

Answer:

0 Explanation:

A tricky ONE. Given 3 points are colinear. Hence, it is a straight line. Hence area of triangle is 0.

9.7845

Qn.6 Silu and Meenu were walking on the road.Silu said, "I weigh 51 Kgs. How much do you weigh?"Meenu replied that she wouldn't reveal her weight directly as she is overweight. But she said, "I weigh 29 Kgs plus half of my weight."How much does Meenu weigh?

60

56

59

58

Answer: 58

Explanation:

It is given that Meenu weighs 29 Kgs plus half of her own weight. It means that 29 Kgs is the other half. So she weighs 58 Kgs.

Qn.7 Consider the sum: ABC + DEF + GHI = JJJ .If different letters represent different digits, and there are no leading zeros, what does J represent?

5

6

8

9

Answer:

9 Explanation:

The value of J must be 9.Since there are no leading zeros, J must be 7, 8, or 9. (JJJ = ABC + DEF + GHI= 14? + 25? + 36? = 7??)Now, the remainder left after dividing any number by 9 is the same as the remainder left after dividing the sum of the digits of that number by 9. Also, note that 0 + 1 + ... + 9 has a remainder of 0 after dividing by 9 and JJJ has a remainder of 0, 3, or 6. The number 9 is the only number from 7, 8 and 9 that leaves a remainder of 0, 3, or 6 if you remove it from the sum 0 + 1 + ... + 9. Hence, it follows that J must be 9.

Qn.8 A person travels at a speed of 4kmph from A to B and returns to A with a speed of 5Kmph. Find his average speed.?

4.50

4.44

Answer:

4.44

Explanation:

Average speed = total distance / total time taken Let the distance from A to B be x. Let t1 be the time taken from A to B and t2 be the time taken from B to A (returning time). Then average speed = 2x / (t1 + t2) Here t1 = x/4 and t2 = x/5 (speed = distance/time formula is applied here) Applying these values in the first equation we will get average speed = 4.44.

4.60

4.48

Qn.9 Consider two cars A and B. Speed of A is 10 Kmph. Speed of B is 3 times faster than that of A. What will be the ratio of time taken by B to cover the same distance as that of A.

2/5 1/3

Answer: 1/3 Explanation:

Speed of B = 3 X 10 = 30 Kmph. Hence B can cover 3 times the distance that can be covered by B in a given time. In other words, B takes one third or 1/3 of time taken by A to cover the same distance. Hence answer would be 1/3.

1/5

3/5

Qn.10 The ratio of Rita's age to her mother's age is 3:8. The difference of their ages is 35 years. The ratio of their ages after 4 years will be ------ .

3:11

5:12

Answer:

5:12 Explanation: Let their ages be 3x and 8x 8x - 3x =35 x =7 Their present ages are 21 and 56 years. Ratio of their ages after 4 years are 25:60 = 5:12

6:15

7:18

Qn.11 m*n^2 * ( m + n^2 ) = 2^13 . Solve for m and n by deduction.

4 & 16

Answer:

4 & 16

Explanation:

Assuming that we're looking for integers, m, n^2, and m + n^2 are all powers of 2. The third is only possible if m = n^2. Let m = 2^x, then 2^x * 2^x * 2^(x+1) = 2^13 3x + 1 = 13 x = 4 which gives m = 16, n = 4. 2 & 8

3 & 27

5 & 125

Qn.12 The total number of digits in all the page numbers, of a book I am reading now, is 1689 . How many pages does my Book have ? 479 527 599 608

Qn.13 Using two 2's and two 3's and using a maximumm of three mathematical signs, symbols, can you have a result in between 14 and 15 ?

13.5 12 14 14.5

Answer: 14.5

Explanation:

( 23 + 3! ) / 2 = 14.5

Qn.14 If one-seventh of a number exceeds its eleventh part by 100 then the number is...

770 1100 1825 1925 Answer:

1925 Explanation: Let the number be x. Then X/7 - x/11 =100 11x-7x = 7700 x=1925.

Qn.15 1!*2!*3!*4!* 5!*6!*... ......... ......100! . Find the number of zero?

1020 1220 1460 1520

Qn.16 a*b*c*d*e + b*c*d*e*f + a*c*d*e*f + a*b*d*e*f + a*b*c*e*f + a*b*c*d*f = a*b*c*d*e*f and a,b,c,d,e and f are all positive no repeating integers then Solve a,b,c,d,e, and f

2, 6. 16.36,125

2,3,9,27,81,162

3.9,27,100,144

3,9,36,121,169

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